1. A cell containing a 3% sucrose solution is placed into a beaker containing a 7% sucrose solution. Assume the cell’s membrane is permeable to water, but not permeable to the sucrose. Where will the water diffuse? 2. True or false: Each turn of the Calvin cycle produces one molecule of glucose? If false, how would it be true?

1. A cell containing a 3% sucrose solution is placed into a beaker containing a 7% sucrose solution. Assume the cell’s membrane is permeable to water, but not permeable to the sucrose. Where will the water diffuse? – The water will diffuse towards the beaker (into the beaker’s solution)
2. True or false: Each turn of the Calvin cycle produces one molecule of glucose? If false, how would it be true? –False – 6 turns of calvin cycle forms one molecule of glucose,

Explanation:

1. A cell containing a 3% sucrose solution is placed into a beaker containing a 7% sucrose solution. Assume the cell’s membrane is permeable to water, but not permeable to the sucrose. Where will the water diffuse?

The cell has 3% sucrose solution
The beaker has 7% sucrose solution
This implies that there is high solute concentration in the beaker compared to the cell. Thus, the beaker’s solution is hypertonic to the cell.
If the cell is permeable to water only, we do not expect sucrose to cross between the two compartments, but water will diffuse towards the side with the higher solute concentration through osmosis.
Thus, water will diffuse into the beaker.