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# How many grams of K2SO4 are required to prepare 750 mL of a 0.050 M solution?

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 ▲ 0 ▼ ♥ 0 How many grams of K2SO4 are required to prepare 750 mL of a 0.050 M solution?

### ✅ Answers (1)

 ▲ 0 ▼ ✔ Private answer How many grams of K2SO4 are required to prepare 750 mL of a 0.050 M solution? Top of Form Answer Mass = 6.53 grams Explanation: How many grams of K2SO4 are required to prepare 750 mL of a 0.050 M solution? Concentration = Moles / Volume (L) Moles = mass / molar mass Moles = Concentration * Volume (L) Moles = 0.050 M * 0.750 L = 0.0375 moles moles = mass / molar mass 0.0375 = mass / 174.259 g/mol Mass = 174.259 * 0.0375 Mass = 6.53 grams Top of Form   Marked as spam Answered on June 21, 2020 8:14 am

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