How many moles of H are present in 10.0 L of hydrogen sulfide gas (H2S) at 2.00 atm and 274 K, assuming it obeys the ideal gas law? [Do not include the units in your answer]

How many moles of H are present in 10.0 L of hydrogen sulfide gas (H2S) at 2.00 atm and 274 K, assuming it obeys the ideal gas law? [Do not include the units in your answer]

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Answer

• Answer = 89
  Explanation:
  Ideal gas equation
  PV = nRT
  P = 2 atm
  V = 10 L
  n = moles
  R = 0.0821 atm•L/mol•K
  T = 274 K
  2 * 10 = n * 0.0821 * 274
  20 = n * 22.5
  20 / 22.5 = n
  n (moles) = 0.89 moles