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# SO2 reacts with H2S as follows: 2H2S + SO2 –> 3S + 2H2O When 7.50 g of H2S reacts with 12.75 g of SO2, which statement is true?

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 ▲ 0 ▼ ♥ 0 SO2 reacts with H2S as follows: 2H2S + SO2 –> 3S + 2H2O When 7.50 g of H2S reacts with 12.75 g of SO2, which statement is true? A.H2O is the limiting reagent B.H2S is the limiting reagent C.SO2 is the limiting reagent D.S is the limiting reagent

### ✅ Answers (1)

 ▲ 0 ▼ ✔ Private answer SO2 reacts with H2S as follows: 2H2S + SO2 –> 3S + 2H2O When 7.50 g of H2S reacts with 12.75 g of SO2, which statement is true? A.H2O is the limiting reagent B.H2S is the limiting reagent C.SO2 is the limiting reagent D.S is the limiting reagent Top of Form Answer H2S is the limiting reagent Explanation: 2H2S + SO2 –> 3S + 2H2O Mole ratio of 2H2S : SO2 = 2 : 1 Amount of each reagent in moles Moles = mass / molar mass 2H2S Moles = 7.5 g / 34 g/mol = 0.22 moles Moles of SO2 12.75 g / 64 g/mol = 0.2 moles According to the equation, 2 moles of H2S requires 1 mole of SO2 Thus, 0.22 moles will require = 0.22 moles * 1 / 2 = 0.11 moles of SO2 Available moles of SO2 is 0.2, while the amount required by H2S for the reaction is 0.11. This implies that H2S is in excess of (0.2-0.11) 0.09 moles The limiting reagent is H2S because it requires less SO2 than what is available   Marked as spam Answered on June 21, 2020 8:19 am

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