Suppose you have a fixed container containing 0.255 moles of a gas (the identity of the gas doesn’t matter). If the container volume is 0.748 L, and the temperature is 301.15 K, what is the pressure in atm? (R = 0.0821 L∙atm/mol∙K)

Answer

Pressure = 7.44 atm

Explanation

Suppose you have a fixed container containing 0.255 moles of a gas (the identity of the gas doesn't matter). If the container volume is 0.748 L, and the temperature is 301.15 K, what is the pressure in atm? (R = 0.0821 L∙atm/mol∙K)

Ideal gas law eqaution

PV = nRT

P = Pressure ?

V = Volume = 0.748 L

n = Moles = 0.225 moles

R = Constant = 0.0821 L∙atm/mol∙K

T = Temperature = 301.15 K

P = nRT / V

P = 0.225 * 0.0821 * 301.15 / 0.748

P = 7.44 atm

Pressure = 7.44 atm