What is the volume, in liters, occupied by 2.12 moles of N 2 gas at 0.745 atm pressure and a temperature of 55 °C? a.12.8 L b.76.6 L c.89.4 L d.42.5 L

What is the volume, in liters, occupied by 2.12 moles of N 2 gas at 0.745 atm pressure and a temperature of 55 °C?
a.12.8 L
b.76.6 L
c.89.4 L
d.42.5 L

Answer

• b.76.6 L

Explanation:
What is the volume, in liters, occupied by 2.12 moles of N 2 gas at 0.745 atm pressure and a temperature of 55 °C?
Ideal gas law
PV = nRT
P = 0.745 atm
V = ?
n = 2.12 moles
R = 0.0821 atm•L/mol•K
T = 55 °C + 273 = 328 K
0.745 * V = 2.12 * 0.0821 * 328
0.745V = 57.09
V = 57.09 / 0.745
Volume = 76.63 L or 76.6 L ( 1 d.p)