You take 125 mL of a stock solution that is 15.0 % solution of MgCl2(aq) and dilute it to a final volume of 500 mL. What is the new concentration of the MgCl2(aq)?

Answer

The new concentration is 3.75%

Explanation

You take 125 mL of a stock solution that is 15.0 % solution of MgCl2(aq) and dilute it to a final volume of 500 mL. What is the new concentration of the MgCl2(aq)?

Formula

MaVa = MbVb

Ma = Concentration of stock solution

Va = Volume of stock solution

Mb = Final concentration

Vb = Final volume

125 * 15% = 500 * Mb

Mb = 125 * 15% / 500

Mb = 3.75%

The new concentration is 3.75%